4x+10 >= 11
4x+10-10 >= 11-10 .... subtract 10 from both sides
4x >= 1
4x/4 >= 1/4 .... divide both sides by 4
x >= 1/4
x >= 0.25
This means x must be 0.25 or larger. The next integer closest to 0.25, that is above 0.25, is the value 1.
So x = 1 is the smallest integer solution possible.
Using The Almighty Formula (attached)
Note the symbol ^ is used to denote a raise to power
Where from the equation given x^2-5x-7
With a,b,c coefficients
a=1 b=-5 c=-7
From the Almighty Formula
√b^2-4ac=√(-5)^2-4(-7)=√53
Substituting in the Almighty Formula
-(-5) ±√53/2(1)= 5±√53/2
x=5+√53/2 and x=5-√53/2
Answer:
x = 2
Step-by-step explanation:
12/7.5 = 1.6
x+6/2x+1 = 1.6
to find the value of x :

x + 6 = 3.2x + 1.6
x - 3.2x = 1.6 - 6
- 2.2x = - 4.4
- x = - 4.4/2.2
- x = - 2
x = 2
Answer:
Step-by-step explanation:
4h/4=92/4
h=23.
thx.