Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
21
Step-by-step explanation:
To find the mean, add up all the numbers
15+15+25+29 =84
Divide by the number of numbers
84/4 = 21
4/5 is your answer
Hope this helps
Same here, we do a quick switcharoo on the variables first,
Answer:
its 6.40
Step-by-step explanation:
you have to use the distance formula which is
so points C is (-5,-1) and D is (0,3)
then you substitute the x
0--5=5^2
then
3--1+4^2=16
25+16=41
then square rout that and it equals 6.40
