How can i show 5/8 is greater than 3/8
2 answers:
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Question 1:
Look at the image.
First, we graph the points on a grid.
Then, we find the perpendicular bisectors and find where they intersect.
They intersect on the circumcenter of the triangle.
The circumcenter is (5,3)
Question 2:
The answer is III only because the perpendicular bisector for the longest side will always have to point outside the triangle in order to intersect with the other two perpendicular bisectors.
Question 3:
The answer is a perpendicular bisector because it is a perpendicular line that bisects a side of the triangles, which is the exact definition of a perpendicular bisector.
Have an awesome day! :)
Look at the image.
First, we graph the points on a grid.
Then, we find the perpendicular bisectors and find where they intersect.
They intersect on the circumcenter of the triangle.
The circumcenter is (5,3)
Question 2:
The answer is III only because the perpendicular bisector for the longest side will always have to point outside the triangle in order to intersect with the other two perpendicular bisectors.
Question 3:
The answer is a perpendicular bisector because it is a perpendicular line that bisects a side of the triangles, which is the exact definition of a perpendicular bisector.
Have an awesome day! :)
Answer:
cos B =
tan B =
sin B =
Step-by-step explanation:
In the right triangle, there are three sides and 2 acute angles
- Hypotenuse ⇒ the opposite side of the right angle
- Leg1 and Leg 2 ⇒ the sides of the right angle
The trigonometry functions of one of the acute angles Ф are
- sin Ф = opposite leg/hypotenuse
- cos Ф = adjacent leg/hypotenuse
- tan Ф = opposite leg/adjacent leg
In Δ ACB
∵ ∠C is the right angle
∴ AB is the hypotenuse
∵ AC is the opposite side of ∠B ⇒ leg1
∵ CB is the adjacent side of ∠B ⇒ leg2
→ By using the ratios above
∴ cos B = , tan B =
, sin B =
∵ CB = 7, AB = 25, AC = 24
∴ cos B =
∴ tan B =
∴ sin B =