Calculate the risk measure (beta) compared to the returns of asset and market premium.
1.4 = 4 + 9((rm^-4)
1.4 = 9rm ^-32
33.4 = 9rm
Rm = 3.71
The answer is 3.71
I've already been complemented twice on my previous answer, but then I discovered that I mis-read the question. My entire original answer was wrong, and I have to delete it.
I don't believe that any number can satisfy both of those conditions.
I'll say the question has no answer.
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
Learn more about probability at brainly.com/question/24756209
#SPJ4
Area of a triangle = 1/2 × base × height
Plug in what we know.
78 = 1/2 × b × 9¾
Multilply each side by 2 to get rid of the 1/2...
156 = b × 9¾
Write 9¾ as an improper fraction.
(9¾ = 9 + 3/4 = (9×4)/4 + 3/4 = 36/4 + 3/4 = 39/4)
156 = b × 39/4
Multiply each side by 4...
624 = b × 39
Divide each side by 39...
16 = b
Done! The length of the base of the triangle is <u>16</u> inches.
