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den301095 [7]
2 years ago
12

Round 721295.198715 to the nearest ten.

Mathematics
1 answer:
zimovet [89]2 years ago
4 0

Answer:

7212960

Step-by-step explanation:

You have to round up since the number in the ones place is a 5.

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I need help please can someone help me find each area thank you
nikitadnepr [17]

Answer:

it is easy use the formula of triangle which is 1/2(base × height) and base is the side where the height touches and height means the perpendicular line.

And in some cases there may be the use of pythagoras theorem

8 0
2 years ago
Read 2 more answers
A survey of middle school students asked if they play video games. The responses are
kow [346]

Answer:

A. 35.69%

B. 62.77%

Step-by-step explanation:

In this case, what we must do is calculate the probability supported with the data in the table.

Part A.

What is the probability that a randomly selected student is a 7th grader?

Here the total is all the students that would be the sum of all the grades, which are 325 students.

the number of 7th graders is 116, so the probability is:

116/325 = 0.3569

that is, 35.69%

Part B: What percentage of the students interviewed play Video games?

The total number of students is the same 325 and of those 204 play video games, therefore:

204/325 = 0.6277

that is, 62.77%

6 0
2 years ago
Which of the following are ways whole numbers and rational numbers are different? Select all that apply. ︎whole numbers are a su
mihalych1998 [28]

Answer:

asd

Step-by-step explanation:

asd

8 0
3 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
2 years ago
Please answer this question! PLEASE! Make advertisement for Asian trade goods that change European life.
Monica [59]
Some spices Were traded from asia to europe. Some include pepper, cloves, cinomin, and nut meg. Some of these spices could cover up the taste of spoiled meat. Most europeans loved them.
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