Solve for t. 6t plus 5t equals negative 11

ExtremeBDS [4]

Answer:

0≤x≤8

Step-by-step explanation:

the domain is basically all the x-values that are applicable to the graph.

Here we can clearly see that the graph starts at x = 0 and ends at x = 8. There are no other possible x-values which is applicable to the graph,

hence the domain is 0≤x≤8

6 0

2 years ago

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A student earned a grade of 80% on a math test that had 20 problems. How many problems on this test did the student answer corre

boyakko [2]

Answer:

16 problems.

Step-by-step explanation:

100% divided by 20 questions.

100/20 is equal to 5, therefore each question is worth 5 points.

Grade of 80% divided by points per question.

80/5 is 16 so the student answered 16 questions correctly.

6 0

2 years ago

Read 2 more answers

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

2 years ago

Suppose f(x) = x². Find the graph of f(x+3). ???

alexdok [17]

Answer: x^2+3

Step-by-step explanation:

If regular f(x) is equal to x^2, then if you just add 3 to the original, you add 3 to the same x^2. The three becomes a shift upwards on the graph. You put your vertex point up 3 on the vertical line then make your parabola

4 0

3 years ago

Is it linear or exponential

kaheart [24]

The relationship for this function is linear love

4 0

3 years ago