<h3>Hey there </h3><h3>Improper Fraction:

</h3><h3>Mixed number/ Fraction :

</h3><h3>Check to see if it gives your decimal </h3><h3>

</h3><h3>

→

</h3><h3>

→

</h3><h3>We now have:

</h3><h3>Therefore, your result (

) is:

</h3><h3>Good luck on your assignment and enjoy your day!</h3><h3>~

</h3>
Answer:
D. sin m∠C = 2 square root of 5 all over 5
Step-by-step explanation:
The triangle ABC is a right angled triangle. The angle ∠C is where we are asked to find. The side AB measures 6 , AC measures 3 and the side BC measures 3√5.
The longest side of a right angle triangle is the hypotenuse, that means the side with length 3√5 is the hypotenuse.
Therefore side BC is the hypotenuse side and we are asked to find the angle C. AB is the opposite side while AC is the adjacent side.
Using
sin C = opposite/hypotenuse = 6/3√5 = 2/√5 = 2√5/5
cos C = adjacent/hypotenuse = 3/3√5 = 1/√5
Answer:


Step-by-step explanation:
<u>Second-Degree Equation</u>
The second-degree equation or quadratic equation has the general form

where a is non-zero.
There are many methods to solve the equation, one of the most-used is by using the solver formula:

The equation of the question has the values: a=1, b=2, c=4, thus the values of x are


Since the square root has a negative argument, both solutions for x are imaginary or complex. Simplifying the radical

The solutions are

