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Natasha2012 [34]
3 years ago
8

Without this type of feature on a mobile device, a simple swipe gives anyone access to the device. what is the term for this fea

ture?
Computers and Technology
1 answer:
slamgirl [31]3 years ago
4 0
Hey there! Hello!

For this question, I believe the answer will be something along the lines of a passcode/code lock feature. This basically prevents anyone without knowledge of your device's code access to your device, which is especially handy in case you lose it and don't want other to have free reign of your information.

Without it, yeah, anyone can simply swipe into your device (or, press the home button or whatever they did with iOS 10) and use/view information on it.

If you have multiple choice answer and my answer doesn't seem to fit into any of them, let me know and we'll take it from there.

Hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
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Which of the following function declarations correctly expect an array as the first argument?
NARA [144]

Answer:

Only

Option: void f1(float array[], int size);

is valid.

Explanation:

To pass an array as argument in a function, the syntax should be as follows:

functionName (type arrayName[ ] )

We can't place the size of the array inside the array bracket (arrayName[100]) as this will give a syntax error. The empty bracket [] is required to tell the program that the value that passed as the argument is an array and differentiate it from other type of value.

3 0
4 years ago
What does c++ programming mean?
cestrela7 [59]

Answer:

It's an internal joke to say the language is basically C with some extra stuff (like classes)

the "++" is short for

C += 1 or

C = C + 1 which is a common calculation among programmers so they named it C++ to be a more commercial and attractive name than "C with classes"

Explanation:

8 0
3 years ago
Which best describes Sayid’s error?
Sonja [21]
<span>Change "move only through matter" to "move through space and matter."</span>
8 0
3 years ago
Q10: Putting it all together (0.75 points) Here, we'll update the values in dictionary, storing the output in a dictionary calle
Molodets [167]

Answer:

# Code in Python

dictionary={'A':1,'B':2,'C':3,'D':4}

other_dictionary={}

for keys in dictionary:

if dictionary[keys]&1==1:

temp=dictionary[keys]*dictionary[keys]-10*10

other_dictionary[keys]=temp

else:

other_dictionary[keys]=dictionary[keys]

print(other_dictionary)  

assert other_dictionary

Explanation:

  • Initialize a sample example dictionary  and other_dictionary.
  • Do a binary comparision for checking odd number .
  • Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
  • For even: store the original value (from dictionary).
4 0
3 years ago
Assume the following variable definition appears in a program:
AnnZ [28]

Answer:

cout << setprecision(2)<< fixed << number;

Explanation:

The above statement returns 12.35 as output

Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.

The statement starts by setting precision to 2 using setprecision(2)

This is immediately followed by the fixed manipulator;

The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;

Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.

The fixed manipulator is then followed by the variable to be printed.

See code snippet below

<em>#include <iostream>  </em>

<em>#include <iomanip> </em>

<em>using namespace std;  </em>

<em>int main()  </em>

<em>{  </em>

<em> // Initializing the double value</em>

<em> double number = 12.3456;  </em>

<em> //Print  result</em>

<em> cout << setprecision(2)<< fixed << number;  </em>

<em> return 0;  </em>

<em>}  </em>

<em />

4 0
3 years ago
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