Answer: This is copied from the internet:
Step-by-step explanation:
Answer:
For function, every element of the domain must have a unique image in co-domain...
(A)Let us redefine each function as a set of ordered pairs
and see if they satisfy the above condition (A) of a function f1={(1,2),(2,3),(3,4)} ; (4,5) cannot be an ordered pair as 5 does not belong to co-domain , Thus the element 4 of domain does not have an image.
f2={(1,4),(2,3),(2,4),(3,2)(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}
The uniqueness is violated as the elements have not one but many images.
f3={(2,1),(3,2),(3,1),(4,1),(4,2),(4,3)} Not a function as in f2 uniqueness is violated.
f4={(1,4),(2,3),(3,2)(4,1)} It is a function as each element has a unique image.
