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Soloha48 [4]
2 years ago
9

If A={1,2,3}, find the relation in A×S satisfying the condition x+y<5.​

Mathematics
1 answer:
Sonja [21]2 years ago
5 0

Answer: This is copied from the internet:

Step-by-step explanation:

Answer:

For function, every element of the domain must have a unique image in co-domain...

(A)Let us redefine each function as a set of ordered pairs

and see if they satisfy the above condition (A) of a function f1={(1,2),(2,3),(3,4)} ; (4,5) cannot be an ordered pair as 5 does not belong to co-domain , Thus the element 4 of domain does not have an image.

f2={(1,4),(2,3),(2,4),(3,2)(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

The uniqueness is violated as the elements have not one but many images.

f3={(2,1),(3,2),(3,1),(4,1),(4,2),(4,3)} Not a function as in f2 uniqueness is violated.

f4={(1,4),(2,3),(3,2)(4,1)} It is a function as each element has a unique image.

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6m−7)⋅4=left parenthesis, 6, m, minus, 7, right parenthesis, dot, 4, equals ¿Atorado?
mars1129 [50]

Answer:

24m - 28

Step-by-step explanation:

Given the expression (6m−7)⋅4, we are to simplify it. Using the distributive law;

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