Answer:
The constant in your equation is 3
Answer:
(a) 
(b)
Step-by-step explanation:
Let´s use Divided Differences Method of Polynomial Interpolation given by this iteration:
![f[x_k,x_k_+_1,...,x_k_+_i]=\frac{f[x_k_+_1,x_k_+_2,...,x_k_+_i]-f[x_k,x_k_+_1,...,x_k_+i_-_1]}{x_k_+_i-x_k}](https://tex.z-dn.net/?f=f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2B_i%5D%3D%5Cfrac%7Bf%5Bx_k_%2B_1%2Cx_k_%2B_2%2C...%2Cx_k_%2B_i%5D-f%5Bx_k%2Cx_k_%2B_1%2C...%2Cx_k_%2Bi_-_1%5D%7D%7Bx_k_%2B_i-x_k%7D)
k∈[0,n-i]
Thus the Newton polynomial can be written as:
![P_n_-_1(x)=f[x_0]+f[x_0,x_1](x-x_0)+f[x_o,x_1,x_2](x-x_0)(x-x_1)+...+f[x_n,x_n_-_1,...,x_1](x-x_n)(x-x_n_-_1)...(x-x_1)](https://tex.z-dn.net/?f=P_n_-_1%28x%29%3Df%5Bx_0%5D%2Bf%5Bx_0%2Cx_1%5D%28x-x_0%29%2Bf%5Bx_o%2Cx_1%2Cx_2%5D%28x-x_0%29%28x-x_1%29%2B...%2Bf%5Bx_n%2Cx_n_-_1%2C...%2Cx_1%5D%28x-x_n%29%28x-x_n_-_1%29...%28x-x_1%29)
(a) I attached you the procedure in the first table, using it we have:
Operate P(x) using the distributive property:
(b) I attached you the procedure in the second table, using it we have:
Operate P(x) using the distributive property:
Answer:
26.5
Step-by-step explanation:
The table shows that 1/2 of all the students surveyed have one pet.
Answer:
The volume of the hollow ball will be equal to the difference between the volume of a sphere with the outer radius and the volume of a sphere with the inner radius.
Remember that the volume of a sphere of radius R is given by:
V = (4/3)*pi*R^3
where pi = 3.14
Then if R is the outer radius, and r is the inner radius, the volume of the hollow ball is:
V = (4/3)*pi*( R^3 - r^3)
In this case, we have:
R = 200m
r = 100m
Then the volume of the hollow ball is:
V = (4/3)*3.14*( (200m)^3 - (100m)^3)
V = 29,306,666.67 m^3
Now, if this hollow ball is made of iron, we want to find the mass.
Remember the relation:
Mass = Density*Volume.
We know that the density of the iron is:
D = 7300 kg/m^3
Then the mass of this hollow ball is:
M = (7300 kg/m^3)*(29,306,666.67 m^3) = 213,938,666,666.6 kg
