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VashaNatasha [74]
3 years ago
13

Finding Missing Sides in Similar Figures

Mathematics
2 answers:
ivanzaharov [21]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{x}{11}=\frac{52}{4}\\\\ x=\frac{52}{4}*11\\\\x=13*11\\\\x=143

In similar figure all the corresponding angles will be congruent and corresponding sides will be in ratio

vitfil [10]3 years ago
4 0

Answer:

143

Step-by-step explanation:

  1. Identify the similar sides. (91 and 7, 52 and 4, 91 and 7, and 11 and x)
  2. Find the scale factor by dividing two of the corresponding sides (91/7 = 13 or 52/4 = 13)
  3. Now, multiply the scale factor by 11 to find the length of the missing side. (11(13) = 143)
  4. Therefore, the length of the missing side is 143.
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V125BC [204]

Answer:

Option D The solution of the system is the point (-3,5)

Step-by-step explanation:

we have

x+y=2 -----> equation A

y=-2x-1 ------> equation B

Solve the system by substitution

Substitute the equation B in equation A and solve for x

x+(-2x-1)=2

-x-1=2

x=-2-1

x=-3

Find the value of y

y=-2x-1

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therefore

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3 0
3 years ago
PLEASE HELP ME!!! THE RIGHT ANSWER WILL GET THE BRAINIEST!
Lina20 [59]

Answer:

\sf D) \quad s=8 \frac{1}{4}t

Step-by-step explanation:

  • t  = time (in hours) → this is the independent variable
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Therefore, if the rate of cleaning is 8 1/4 square feet per hour, the relationship between s and t is:

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8 0
2 years ago
Which of the following numbers are divisible by 3? 225, 8,399, 7,392, 9,830 (can be more than one answer) I'm very busy so I jus
soldier1979 [14.2K]
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3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

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We can conclude that the probability for 8 rooks not being able to capture themselves is

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