<u>Answer:</u>
<u>Step-by-step explanation:</u>
We have a parabola and a small line shown in the graph.
The parabola goes upto x = 2 but does not reach that very value. So x = 2 starts on the line above where x = 2 and ends just before x = 4.
Therefore, this function can be modeled by:
Answer:
<h2>cosecθ = 1/sinθ = 11/6√2</h2>Step-by-step explanation:
Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.
Based on SOH, CAH, TOA;
cosθ = adjacent/hypotenuse = 7/11
adjacent = 7 and hyp = 11
Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.
Using pythagoras theorem to get the opposite;
sinθ = 6√2/11
cosecθ = 1/sinθ = 1/( 6√2/11)
cosecθ = 1/sinθ = 11/6√2
Note the error; cscθ 1/cosθ but cscθ = 1/sinθ