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kifflom [539]
3 years ago
12

Using the expression 30y – 6c find the value of the expression when: y = -4 and c = 1.

Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

9514 1404 393

Answer:

  -126

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic.

  30(-4) -6(1) = -120 -6 = -126

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Step-by-step explanation:

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The side of each of the equilateral triangles in the figure is twice the side of the central regular hexagon. What fraction of t
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Answer:

The fraction is 1/4

Step-by-step explanation:

we know that

The area of an equilateral triangle, using the law of sines is equal to

A=\frac{1}{2}x^{2}sin(60^o)

A=\frac{1}{2}x^{2}(\frac{\sqrt{3}}{2})

A=x^{2}\frac{\sqrt{3}}{4}

where

x is the length side of the triangle

In this problem

Let

b ----> the length side of the regular hexagon

2b ---> the length side of the equilateral triangle

step 1

Find the area of the six triangles

Multiply the area of one triangle by 6

A=6[x^{2}\frac{\sqrt{3}}{4}]

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=2b\ units

substitute

A=3(2b)^{2}\frac{\sqrt{3}}{2}\\\\A=6b^{2}\sqrt{3}\ units^2

step 2

Find the area of the regular hexagon

Remember that, a regular hexagon can be divided into 6 equilateral triangles

so

The area of the regular hexagon is the same that the area of 6 equilateral triangles

A=3x^{2}\frac{\sqrt{3}}{2}

we have

x=b\ in

substitute

A=3(b)^{2}\frac{\sqrt{3}}{2}

step 3

To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

3(b)^{2}\frac{\sqrt{3}}{2}:6b^{2}\sqrt{3}=\frac{3}{2} :6=\frac{3}{12}=\frac{1}{4}

3 0
3 years ago
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