Question

Pls helps fast!!

Answer 1

Answer:

Option B is correct.

Step-by-step explanation:

We have given a triangle ABC and EDC please look at the figure

We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles

And ∠ACB=∠DCE are vertically opposite angles hence, equal

So, by AA similarity postulate the above to triangles are similar

ΔABC $\sim$ ΔEDC

Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5

NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE

And m∠1 = m∠5 corresponds to m∠EAB=m∠AED