Answer:
Vertex form: f(x) = -10(x − 2)^2 + 3
Standard form: y = -10x^2 + 40x - 37
Step-by-step explanation:
h and k are the vertex coordinates
Substitute them in the vertex form equation:
f(x) = a(x − 2)^2 + 3
Calculate "a" by replacing "f(x)" with -7 and "x" with 1:
-7 = a(1 − 2)^2 + 3
Simplify:
-7 = a(1 − 2)^2 + 3
-7 = a(-1)^2 + 3
-7 = a + 3
-10 = a
Replace a to get the final vertex form equation:
f(x) = -10(x − 2)^2 + 3
Convert to standard form:
y = -10(x − 2)^2 + 3
Expand using binomial theorem:
y = -10(x^2 − 4x + 4) + 3
Simplify:
y = -10x^2 + 40x - 40 + 3
y = -10x^2 + 40x - 37
To multiply whole numbers and fractions, multiply the numerator by the whole number. Example: 1/3×4= 4/3=1 1/3
Answer:
4x?y*[2x2y)
Step-by-step explanation:
Answer:X=5
Step-by-step explanation:
6x + 12 = 42
-12. -12
6x=30
6x. 6
X=5
Check
6(5)+12=42
30+12
42
Answer:
Below
Step-by-step explanation:
First we can go ahead and create a general equation for this polynomial
Here are our roots :
x1 = - 3
x2 = -1
x3 = 1
Now because this function extends from quadrant 4 to 3, we know that this has been reflected in the x-axis :
f(x) = - ( x + 3 ) ( x + 1 ) ( x - 1 )
However if we look closely you can see that the graph appears to "bounce" off certain roots. In this case it bounces off x = 1. This means that this root is an order of 2. It also has a weird looking curve on x = - 3 which means that this root is an order of 3.
Our general equation will look like this :
f(x) = - ( x + 3 )^3 ( x - 1 )^2 ( x + 1 )
Now we need to sub in any point on the graph to solve for the <em>a </em>value. I'm just going to arbitrarily pick the y-intercept at ( 0 , -3 )
- 3 = - a ( 0 + 3 )^3 ( 0 - 1 )^2 ( 0 + 1 )
- 3 = - a (3)^3 (-1)^2 (1)
- 3 = - a (27)(1)(1)
- 3 = - a27
1/9 = a
Here is our FINAL equation :
f(x) = - 1/9 ( x + 3 )^3 ( x - 1 )^2 ( x + 1 )
Hope this helps! Best of luck <3
I would really appreciate a brainliest if possible :)
