Answer:
The equation answer will always be positive
Step-by-step explanation:
Answer:
4/25 or 0.16
Step-by-step explanation:
your welcomeee
Answer:
We don´t have at 95% of confidence, evidence to reject the publisher´s claim
Step-by-step explanation:
Population mean p₀ = 58 % or p₀ = 0,58
Hypothesis Test:
Null Hypothesis H₀ p = p₀
Alternative Hypothesis Hₐ p < p₀
For a significance level α = 0,05 means that CI = 95 % or CI = 0,95
z(c) = - 1,64
MOE = z(c)* √(p*q)/n
p - p₀ / √(p*q)/n = z(s)
And that z(s) is in the acceptance region
|z(s)| < |z(c)|
|z(s)| < 1,64
Then if that so we fail to reject H₀ . We don´t have evidence to reject the publisher´s claim
Using the z-distribution, it is found that she should take a sample of 46 students.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

The margin of error is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Scores on the math portion of the SAT are believed to be normally distributed and range from 200 to 800, hence, by the Empirical Rule the standard deviation is found as follows:



The sample size is n when M = 29, hence:





n = 45.67.
Rounding up, a sample of 46 students should be taken.
More can be learned about the z-distribution at brainly.com/question/25890103
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