Answer:
Angle 1 = 105
Angle 2 = 75
Step-by-step explanation:
Angle 2 and angle 75 are corresponding angles.
Corresponding angles are equal.
So,
Angle 2 = 75
Angle 1 and angle 2 are linear pair angles.
Angle 1 + Angle 2 = 180
Angle 1 + 75 = 180
Angle 1 = 180 - 75
Angle 1 = 105
Vector QP= (-5+6, 11-4) = (1, 7)
its magnitude is QP= sqrt( 1 + 49)= sqrt (50)=5sqrt2
Answer:
y=2/5x-2
Step-by-step explanation:
The main equation you will need for this is y=mx+b
First, you have to find the slope. the equation for that is 
-2-0 = -2 (y)
0-5= -5 (x)
A good way to remember this is rise over run or y is always over x
Slope = 2/5 (The negatives cancel out)
The great thing about this is that they have already given you your "y" intercept or "b" which is -2
<span>x^2+16x+24: Think: What are the integer factors of 24? I'd list 1, 2, 3, 4, 6, 8, 12 and 24. Next: Look for a pair of factors from that list that:
(1)ADD up to 16 AND (2) whose product is 24. Unfortunately there seems to be no such pair from the above list.
So: Use the quadratic formula to find the roots of </span>x^2+16x+24:
-16 plus or minus sqrt[ 256-4(1)(24) ]
x = --------------------------------------------------
2
-16 plus or minus sqrt(160) -16 plus or minus 4 sqrt(10)
= --------------------------------------- = ----------------------------------------
2 2
2(-8 plus or minus 2 sqrt(10) )
= ------------------------------------------- = -8 plus or minus 2sqrt(10)
2
If c is a root, (x-c) is a factor. Thus, if -8 plus 2sqrt(10) is a root,
(x+8-2sqrt(10) is a factor. Can you find the other factor?
x^2-10a+25 is much easier to factor. The sqrt of 25 is 5, so try x= -5 as a root. Dividing x-5 into <span>x^2-10a+25, we get x-5. Therefore, the factors are
(x-5) and (x-5).</span>