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3 years ago

How do i solve v=pi/3*r (squared)h for h

1 answer:

Colt1911 [192]3 years ago

3 0

$V=\dfrac{\pi}{3}\cdot r^2h\ \ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |\divide\ both\ sides\ by\ \pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}$

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2/5 of the students in the class received an invitation to Sari's party. (a) if there are 35 students in Sari's class, how many

astraxan [27]

a) (2/5) x 35 = 14 students received invitations

b) 35-14 = 21 students didn’t receive invitations

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3 years ago

Before conducting some experiments, a scientist mixes 1/2 gram of Substance A with 3/4 grams of Substance B. If the scientist us

Tju [1.3M]

Answer: 10

<u>Step-by-step explanation:</u>

$(\frac{1}{2}+\frac{3}{4})$ ÷ $\frac{1}{8}$

= $(\frac{1}{2}(\frac{2}{2})+\frac{3}{4})$ ÷ $\frac{1}{8}$

= $(\frac{2}{4}+\frac{3}{4})$ ÷ $\frac{1}{8}$

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3 years ago

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3 years ago

Select linear or nonlinear

seraphim [82]

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3 years ago

Read 2 more answers

Task: Nonpermissible Values for Rational Expressions [30 points] Write a rational expression that has the nonpermissible values

igor_vitrenko [27]

Answer:

A rational expression that has the nonpermissible values $x = 0$ and $x = 17$ is $f(x) = \frac{4}{x\cdot (x-17)}$ .

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of $x$ , the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

$f(x) = \frac{p(x)}{q(x)}$ (1)

Then, the factorized form of $q(x)$ must be:

$q(x) = x\cdot (x-17)$ (2)

If we know that $p(x) = 4$ , then the rational expression is:

$f(x) = \frac{4}{x\cdot (x-17)}$ (3)

A rational expression that has the nonpermissible values $x = 0$ and $x = 17$ is $f(x) = \frac{4}{x\cdot (x-17)}$ .

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3 years ago