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sesenic [268]
3 years ago
5

45.3297 rounded to the nearest tenth would be?

Mathematics
1 answer:
Alex3 years ago
5 0
45.3297 rounded to the nearest tenth is 45.3
3 is in the tenths place, so you look at the number to the right of it. If that number is 5 or more, you round up. If the number is 4 or less, you round down. So you round 45.3297 down to 45.3
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Help asap please !! Thank you soooo much t who ever helps.
PSYCHO15rus [73]

A) 2 2/9

The answer would of course be positive because two negatives make a positive.

It would only be 6 4/9 if you added when here it states the obvious for you to subtract.

Hope this helped PLEASE MARK BRAINLIEST!!

6 0
3 years ago
Please help me out.​
grandymaker [24]

Answer:

it's 4

Step-by-step explanation:

big brainnnnnnnnnn

6 0
3 years ago
Read 2 more answers
The average score on a standardized test is 750 points with a standard deviation of 50 points. What is the probability that a st
nalin [4]
The probability that student scored more than 850 we shall proceed as follows:
z=(x-μ)/σ
where:
x=850
μ=750
σ=50
thus
z=(850-750)/50
z=2
thus
P(x>850)=1-P(x<850)=1-P(z<2)=1-0.9772=0.0228

Answer: P(x>850)=0.0228
4 0
3 years ago
Read 2 more answers
A running group has 38 members. Each group member completed half marathon (13.1 miles). The average time to complete is 110 minu
Vikki [24]

Answer:

They took 4,180 minutes total to complete the course.

Step-by-step explanation:

The average time is given by the sum of each individual time of the members divided by the number of members on the group. So if we want to know the total time they took to complete the course we need to take the average and multiply it by the number of people in the group. So we have:

total time = average*number of members = 110*38 = 4180 minutes

They took 4,180 minutes total to complete the course.

8 0
3 years ago
Use the Law of Cosines to find angle round to the nearest tenth if necessary).
ad-work [718]

Answer:

Step-by-step explanation:

3a)

find side HP  , let's set side HP = c in the law of cosines formula

then

c = sq rt [ 23^2 + 12^2 - 2*12*23*cos(117) ]

c = sq rt [ 529 + 144 - (-250.6027559) ]

c = sq rt [ 673 + 250.6027559 ]

c = sq rt [ 923.602755 ]

c = 30.39

then

HP = 30.4  ( rounded to nearest 10th )

3b)

let PR = c, then law of cosines is (we need angle Q also 180=24+97+Q is 59°

c = sq rt [ 9^2 + 22^2 - 2*9*22*cos(59) ]

c = sq rt [ 81 + 484 -396*0.5150380 ]

c = sq rt [ 565 - 203.955 ]

c = sq rt [ 391.04495]

c = 19.7748

PR = 19.8  ( rounded to nearest 10th )

3c)

they want us to find ∠B,   in the formula for cosines ∠B is really ∠C, it's a bit confusing.. I'm sure they did that on purpose to mess people up.  Kind of underhanded  :/    Tell the teacher that you're "appalled" at the deviousness of the test  :/   stage a protest against math that teaches treachery  :P  storm the principals/ dean's  office with paper airplanes and pictures of anime   :DDD  okay back to math.

a=28

b=17

c=15

since we want angle B then the formula looks like

B= arcCos ( a^2 + c^2 - b^2 / 2*a*c)  so we'll avoid messing up the which side is which ... by setting up the formula this way   .. got it?

B = arcCos [28^2 + 15^2 - 17^2 / 2*28*15]

B = arcCos[784 + 225 - 289 /840 ]

B = arcCos[720/ 840]

B = arcCos[0.85714285]

B = 31.0027 °

that it came out so close to an integer I'm pretty sure it's right

∠B = 31 .0 °  ( rounded to the nearest 10th )

3d)

find ∠A

set it up carefully again, they are asking us to move the variable around again

a = 18

b= 28

c= 12

then the formula looks like

∠A = arcCos[ b^2 + c^23 - a^2 / 2*b*c ]

∠A = arcCos[28^2 + 12^2 - 18^2 /2*28*12 ]

∠A = arcCos[784 + 144 -324 / 672 ]

∠A = arcCos[604/672]

∠A = arcCos[0.8988095]

∠A =25.99797 °

∠A =26.0 °  ( rounded to nearest 10th)

7 0
3 years ago
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