I need all the answers

can someone please help me with this question!!

valkas [14]

Answer:

B' (-4, -4)

Step-by-step explanation:

When you dilate from the origin, you multiply the coordinate points by the scale factor.

B (-1, -1) × 4 = B' (-4, -4)

I hope this helps :))

7 0

3 years ago

Show that area under multivariate normal distribution over the whole range in unity. Find characteristics function of multivaria

kenny6666 [7]

Answer:

here is the answer

Step-by-step explanation:

you may please search it

8 0

3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken if the desir

Ksju [112]

Answer:

We need a sample size of at least 75.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, we find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The standard deviation is the square root of the variance. So:

$\sigma = \sqrt{484} = 22$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is

We need a sample size of at least n, in which n is found when M = 5. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$5 = 1.96*\frac{22}{\sqrt{n}}$

$5\sqrt{n} = 43.12$

$\sqrt{n} = \frac{43.12}{5}$

$\sqrt{n} = 8.624$

$(\sqrt{n})^{2} = (8.624)^{2}$

$n = 74.4$

We need a sample size of at least 75.

6 0

3 years ago

Read 2 more answers

A small-appliance manufacturer finds that the profit P (in dollars) generated by producing x microwave ovens per week is given b

Olegator [25]

Answer:

Number of ovens must be manufactured in a given week to generate a profit of $1610 is 70

Step-by-step explanation:

We are given

A small-appliance manufacturer finds that the profit P (in dollars) generated by producing x microwave ovens per week is given by the formula

$P=\frac{1}{10}x(300-x)$

provided that 0 ≤ x ≤ 200

We are given

profit is $1610

so, we can set P=1610

and then we can solve for x

$1610=\frac{1}{10}x(300-x)$

Multiply both sides by 10

$1610\cdot \:10=\frac{1}{10}x\left(300-x\right)\cdot \:10$

$16100=x\left(300-x\right)$

$16100=300x-x^2$

$-x^2+300x-16100=0$

now, we can factor it

$(x-70)(x-230)=0$

we can solve for x

and we get

$x=70,x=230$

Since, x=230 does not lie on 0 ≤ x ≤ 200

So, we will consider only x=70

So,

Number of ovens must be manufactured in a given week to generate a profit of $1610 is 70

7 0

3 years ago

Accountants at the Tucson firm, Larry Youdelman, CPAs, believed that several traveling executives were submitting unusually hi

77julia77 [94]

Answer:

a) $Y= 90 +46.50(5) +0.35 (340) =441.50$

b) The accountant should not question the voucher as the request is much higher than expected.

c) We can add the following variables

d) The percentage of variation in the trip cost that can be explained by the model = (0.64)^2 =0.4096 or 40.96%

A. Type of travel (air/car)

B. Gender of the executive (male/female)

The last option is not too important since we are analyzing the traveling executives not the type of business

Step-by-step explanation:

Part a

For this case we have the multiple regression model given by:

$Y= 90 +46.50 x_1 +0.35 x_2$

Where $x_1$ represent the number of days on the road and $x_2$ the distance traveled in miles.

And we want to find the expected amount from a 340-mile trip that took her out of town for 5 days, so we just need to replace x1= 5 and x2=340 and we got:

$Y= 90 +46.50(5) +0.35 (340) =441.50$

Part b

The expected value taking in count that x1 = 5 and y = 340 is:

$Y= 90 +46.50(55) +0.35 (340) =441.50$

And the difference from the obtained value is : 685-441.50=243.5

So then the correct answer would be:

The accountant should not question the voucher as the request is much higher than expected.

Part c

We can add the following variables

A. Type of travel (air/car)

B. Gender of the executive (male/female)

The last option is not too important since we are analyzing the traveling executives not the type of business

Part d

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

The coefficient of determination "is a measure used in statistical analysis that assesses how well a model explains and predicts future outcomes. It is indicative of the level of explained variability in the data set".

The percentage of variation in the trip cost that can be explained by the model = (0.64)^2 =0.4096 or 40.96%

6 0

3 years ago