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dimulka [17.4K]
3 years ago
14

Can you help me Graph y= -x - 6?

Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0
Plot point(0,-6). Then go down 1 and 1 to the right locate another point(1,-7) connect (0,-6) and(1,-7) and extended from both sides
You might be interested in
Which recursive definition could be used to generate the sequence {3, 6, 3, 6, 3,...}?
PIT_PIT [208]

The recursive definition used to generate the sequence {3, 6, 3, 6, 3,...} is:

a_n = a_{n - 1} + 3(-1)^n where a_1 = 3 and n\geq 2

<em><u>Solution:</u></em>

Given sequence is 3, 6, 3, 6, 3,...

To find: recursive definition for the sequence

First term in the sequence is 3

Then you add on 3 to get to 6 as the second term

Then add -3 to get 3 as third term

This pattern goes on forever

3 + 3 = 6

6 - 3 = 3

3 + 3 = 6

6 - 3 = 3

and so on

<em><u>So we can generate a recursive definition as:</u></em>

Let a_n be the nth term and "n" denotes the term's location

a_1 is the first term of sequence

a_n = a_{n - 1} + 3(-1)^n , where a_1 = 3 and n\geq 2

Here, 3(-1)^n is used to denote , we add on either +3 or -3 to the previous term to get next term

7 0
3 years ago
Given z1 = 2 + sqrt 3i and z2 = 1 – sqrt 3i, what is the sum of z1 and z2?
icang [17]

Answer:

its B. 3

^-^

Step-by-step explanation:

7 0
3 years ago
HOW DO YOU DO THIS? PLEASE HELP
Savatey [412]
I don’t see a picture is there one anyway
8 0
3 years ago
W many large
ankoles [38]

Answer:

5

Step-by-step explanation:

40 / 7.50 = 5.3 recurring

Seeing as you can't buy 0.3 of a pizza, we just use the 5

8 0
3 years ago
Read 2 more answers
Find the square. (1/4A + 1/4B)^2<br><br> a) 1/16A^2 + 1/8AB + 1/16B^2<br> b) 1/4A^2 + 1/8AB + 1/4B^2
alisha [4.7K]

(a + b)^2 = a^2 + 2ab + b^2

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2

Answer: A.

Another way to solve by factoring 1/4.

(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =

= [\dfrac{1}{4}(A + B)]^2

= (\dfrac{1}{4})^2(A + B)^2

= \dfrac{1}{16}(A^2 + 2AB + B^2)

= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2

= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2

6 0
4 years ago
Read 2 more answers
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