8 is 1/6 of 8/6 = 1 1/3
125 is 5/10 of 625/10 = 62 1/2
32 is 4/10 of 128/10 = 12 4/5
Answer:
Option: D is correct.
Step-by-step explanation:
since we are given a inequality as:

Clearly from the graph of the following inequality we could see that the origin is included in the shaded region and the shaded area is below the line.
Also it could be seen that if we put the origin points i.e. (0,0) in the inequality than 0<2 and the condition is true and hence origin is included in the shaded area.
Hence, option D is true.
Answer:
The surface area is equal to 
Step-by-step explanation:
The surface area of the triangular pyramid is equal to the area of its four triangular faces
so
In this problem
![SA=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have


substitute the values
![SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2815%29%2813%29%5D%3D390%5C%20in%5E%7B2%7D)
The interval notation is 
Explanation:
The inequality is 
Let us complete the square, we get,

Simplifying, we have,


Adding both sides of the equation by 11, we get,

Since, we know that for
, if n is even then ![-\sqrt[n]{a}](https://tex.z-dn.net/?f=-%5Csqrt%5Bn%5D%7Ba%7D%3Cu%3C%5Csqrt%5Bn%5D%7Ba%7D)
Thus, writing the above expression in this form, we get,

Also, if
then
and 
Then ,we have,
and 
Solving the inequalities, we get,
and 
Merging the intervals, we have,

Hence, writing the solution in interval notation, we have,

Therefore, the answer is 