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sweet [91]
3 years ago
10

Simplify the following expression. one-fourth(16 – 12x) (1 point) 4 + 3x 4 – 3x 4 + 3 4 – 3

Mathematics
1 answer:
Bad White [126]3 years ago
5 0

Given expression: 1/4 (16-12x).

Solution: We can see that 1/4 is in front of paranthesis.

That represents multiplication of 1/4 with (16-12x)

In order to 1/4 with (16-12x), we need to distribute 1/4 over (16-12x).

On distributing 1/4 over (16-12x), we get

1/4 (16-2x) = 1/4 * 16 + 1/4 * (-12x).

On multiplying 1/4*16, we get 16/4 and 1/4 * (-12x) = -12x/4.

16/4 could be simplify to 4 and -12x/4 could be simplify to -3x.

So, final answer would be 4 - 3x.

Therefore, second option is our correct option, that is 4 - 3x.

You might be interested in
8 is 1/6 of what number
charle [14.2K]

8 is 1/6 of 8/6 = 1 1/3

125 is 5/10 of 625/10 = 62 1/2

32 is 4/10 of 128/10 = 12 4/5

6 0
3 years ago
Read 2 more answers
Find NL. Not sure to to solve this.
Paul [167]

Answer:

NL= 2 × HI

x+24 =2 × (X+16)

x+24=2x + 32

2x-x= 24-32

x= – 8

NL=x+24 = –8 +24= 16

So ; NL= 16

I hope I helped you^_^

4 0
3 years ago
Read 2 more answers
Determine whether the origin is included in the shaded region and whether the shaded region is above or below the line for the g
kati45 [8]

Answer:

Option: D is correct.

Step-by-step explanation:

since we are given a inequality as:

y

Clearly from the graph of the following inequality we could see that the origin is included in the shaded region and the shaded area is below the line.

Also it could be seen that if we put the origin points i.e. (0,0) in the inequality than 0<2 and the condition is true and hence origin is included in the shaded area.

Hence, option D is true.

6 0
4 years ago
The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch
DedPeter [7]

Answer:

The surface area is equal to 390\ in^{2}

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

so

In this problem

SA=4[\frac{1}{2}(b)(h)]

we have

b=15\ in

h=13\ in

substitute the values

SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}

4 0
3 years ago
Read 2 more answers
Solve the inequality and express your answer in interval notation<br> x^2+8x+5 &lt;0
irakobra [83]

The interval notation is (-\sqrt{11}-4, \sqrt{11}-4)

Explanation:

The inequality is x^{2}+8 x+5

Let us complete the square, we get,

x^{2}+8 x+5+4^{2}-4^{2}

Simplifying, we have,

(x+4)^{2}+5-4^{2}

(x+4)^{2}-11

Adding both sides of the equation by 11, we get,

(x+4)^{2}

Since, we know that for u^{n} , if n is even then -\sqrt[n]{a}

Thus, writing the above expression in this form, we get,

-\sqrt{11}

Also, if a then a and u

Then ,we have,

-\sqrt{11} and x+4

Solving the inequalities, we get,

-\sqrt{11}\ \ \ \ \ \  and  x+4

Merging the intervals, we have,

-\sqrt{11}-4

Hence, writing the solution in interval notation, we have,

(-\sqrt{11}-4, \sqrt{11}-4)

Therefore, the answer is (-\sqrt{11}-4, \sqrt{11}-4)

7 0
4 years ago
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