See attached file. show all work.
1 answer:
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7 . The normal line's equation is x +5y = 17 .
You might be interested in
Answer:
7, I believe. I have to fill in the extra character space, so I hope you have a nice day :)
Answer:
least common denominator=6
Step-by-step explanation:
For the fractions, 1/3 and 1/6th, 3*2=6. making the fraction 2/6 and leaving the other the same 1/6th.
Answer:
1125000
Step-by-step explanation:
just multiply them all
Answer:
The answer is 3x^2-4x-4+1/2x-1
Step-by-step explanation:
Hope this helps, and sorry if it's wrong.
In order to be perpendicular, you must have a slope that is the opposite reciprocal, so the slope should by -3/4. So the equation could be y = -3/4x with any other number at the end.
