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djverab [1.8K]
3 years ago
11

See attached file. show all work.

Mathematics
1 answer:
andrew11 [14]3 years ago
3 0

The point-slope form of the equation for a line can be written as

... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)

Your function gives

... f'(h) = m

... f(h) = k

a) The tangent line is then

... y = 5(x -2) +3

b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.

... y = (-1/5)(x -2) +3

_____

You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.

In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.

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Answer:

V = -9

Step-by-step explanation:

-15V - 40 = 23 - 8V

The objective is to get V alone. To do this, first subtract -15V from both sides. Since -15V is a negative, subtracting it will be adding a positive.

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Now that there is only one term with the variable V, subtract 23 from both sides.

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Finally, divide both sides by 7 to get V completely isolated.

-9 = V.

The final answer is V = -9.

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