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3 years ago

Someone help me please

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

8 0

Answer:

You answer should be -12.

Step-by-step explanation:

b2−4ac

=(6)^2−4(4)(3)

=−12

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Please help multiple choice !!

professor190 [17]

The answer is x= 2, y= 1

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2 years ago

In AWXY, X = 700 cm, w = 710 cm and Angle W= 249. Find all possible values of Angle X, to the nearest 10th of a degree.

LekaFEV [45]

Answer:

Step-by-step explanation:

4 0

2 years ago

Which math expression means "44 more than an unknown number"?

worty [1.4K]

Answer: C. X + 44

Step-by-step explanation:

Let x be the unknown number.

Given statement : "44 more than an unknown number".

By using addition operation ,

Mathematical expression for "44 more than an unknown number" = 44 +x

Hence, the correct expression is x+44.

So, the correct option is C.

5 0

2 years ago

If 8 km = 5 miles, convert 240 km into miles.<br> Can you give that faster? please.<br> Thank you

topjm [15]

Answer:

that is 149.129 miles (thats the answer)

7 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

2 years ago