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77julia77 [94]
3 years ago
14

Show that each fn is bounded on A, but the pointwise limit f of the sequence is not bounded on A. Does (fn) converge uniformly t

o f on A?

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

It seems your question is not complete, but i will asume it is like the one in the image.

Step-by-step explanation:

Answer at the image

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Rewrite the expression in the form y^n
bazaltina [42]

Answer:

$ y^6 $

Step-by-step explanation:

$ \frac{a^b}{a^c} = a^{b - c} $

Using this rule we have:

$ \frac{y^{-7}}{y^{-13}}  = y^{-7 -(-13)} = y^6$

6 0
3 years ago
Read 2 more answers
Admission for a movie is $8 for children and $12 for adults. On a certain day, 3200 people attend the movie theater and $33,040
Nezavi [6.7K]
Let us assume the number of children attending the movie = x
Let us also assume the number of adults attending the movie = y
Cost of admission for a children in the movie = $8
Cost of admission of an adult in the movie = $12
Number of people going to the movie on a certain day = 3200
Total amount collected from the movie theater = $33040
Then
x + y = 3200
And
8x + 12y = 33040
2x + 3y = 8260
Let us first take the equation
x + y = 3200
x = 3200 - y
Now we will put the value of x in the equation
2x + 3y = 8260
2(3200 - y) + 3y = 8260
6400 - 2y + 3y = 8260
y = 8260 - 6400
   = 1860
Now we will put the value of y from the above deduction in the equation
x + y = 3200
x + 1860 = 3200
x = 3200 - 1860
   = 1340
So the number of children going to the movie theater is 1340 and the number of adults going to the movie theater is 1860.
5 0
3 years ago
How can I use multiplication to find the quotient and evaluate the expression
adell [148]
When you divide two fractions, you do Keep, Change, Flip or KCF. So you keep the 3/5, you change the division sign to a multiplication sign, then flip the 3/15 to 15/3. So the new equation is 3/5x15/3. Then you simply the two sides so it becomes 1/1x3/1.....


Meaning the answer is 3.
8 0
3 years ago
Which table correctly shows all the sample spaces for tossing a coin and rolling an even number on a six-sided number cube?
wlad13 [49]
Alright, so you have to have heads and tails, as well as 3 spots each for each even number. Therefore, we need heads with 2 4 6 as well as tails with 2 4 6  (the third one down in the first picture)
7 0
3 years ago
Read 2 more answers
What are the solution(s) of x2-4-0?
Elanso [62]

Answer:

For x^2 - 4 = 0, x  = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

x^2 - 4 = 0

Now, using the ALGEBRAIC IDENTITY:

a^2 - b^2 = (a-b)(a+b)

Comparing this with the above expression, we get

x^2 - 4 = 0  = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2)   = 0 ⇒ x =  2

and if ( x + 2) = 0   ⇒ x = -2

Hence, for x^2 - 4 = 0, x  = 2, or x = - 2.

4 0
3 years ago
Read 2 more answers
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