How do you solve this problem??

Mathematics

1 answer:

Ad libitum [116K]3 years ago

5 0

Answer: x = 64

Step-by-step explanation:

First, order each of the three right triangles by the lengths of the sides. Each triangle has a small (s) leg, a medium (m) leg, and a hypotenuse (h). You can determine their order visually.

Left Δ: s = 36 m = unknown h = 60

Right Δ: s = unknown m = x h = unknown

Big Δ: s = 60 m = unknown h = 36 + x

Next, notice that you can set up a proportion with the Left and Big triangles using the s and h. We can't use m because it has two unknowns.

$\dfrac{s}{h}:\quad \dfrac{36}{60}=\dfrac{60}{36+x}$

Cross multiply and solve for x:

36(36 + x) = 60(60)

1296 + 36x = 3600

36x = 2304

x = 64

You might be interested in

The first term in the sequence below is 2.

Art [367]

-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9

3 0

2 years ago

The value of 27degree in grade measure is 1. 50 grade 2. 30grade 3. 40grade 4. 45grade

Crank

Answer:

30 grade

Is the answer according

to me

5 0

3 years ago

All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,

Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side $l$ , its diagonal would be $l\sqrt{2}$ , and its area $l^2$

If the big square has a area of 900, this implies that its side is $\sqrt{900}$ , so the two diagonal of squares 2 and 4 added together would be $\sqrt{900}$ , therefore one diagonal wold be $\frac{\sqrt{900}}{2}$ . and its side $\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}$ . The area (of one square) is $(\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}$