Answer:
<em> f ( x ) = - 2x^2 + 3x + 1</em>
Step-by-step explanation:
If f ( x ) extends to → − ∞, as x→ − ∞ , provided f(x) → − ∞, as x → +∞, we can rewrite this representation as such;
− ∞ < x < ∞, while y > − ∞
Now the simplest representation of this parabola is f ( x ) = - x^2, provided it is a down - facing parabola;
If we are considering a down - facing parabola, the degree of this trinomial we should create should be even, the LCM being negative. Knowing that we can consider this equation;
<em>Solution; f ( x ) = - 2x^2 + 3x + 1</em>, where the degree is 2, the LCM ⇒ - 2
For the whole thing including the other point it would be [-6, 6] but just for f it should be [6]
Step-by-step explanation:
Richard and teo age is 51 years old
False however a one to one function has to be represented by a straight line the way to test a function is the vertical line test
