All categories

3 years ago

The perimeter of this isosceles triangle is 16cm

Mathematics

2 answers:

Leokris [45]3 years ago

8 0

Answer:

Step-by-step explanation:

nadezda [96]3 years ago

5 0

Answer:

Step-by-step explanation:

Hope I heped

You might be interested in

How would the mean change if the number 52 replaced the number 12 in the set?

m_a_m_a [10]

Answer:

increase

Step-by-step explanation:

First, we need to find the mean of the given data set without any change.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 12 = 264

264 ÷ 8 = 33

Now that we have the mean, we can find the mean of the data set with the change of 52.

10 + 61 + 10 + 44 + 21 + 79 + 27 + 52 = 304

304 ÷ 8 = 38

From this, we can see that the mean has increased with the change of 12 to 52. Thus, that's the correct option.

hope this helps!

6 0

2 years ago

Use the Associative Property of Addition to write an expression equivalent to (n + 2) + 7. Which expression is equivalent to (n

insens350 [35]

Answer:

The correct answer is OB.

Step-by-step explanation:

Let us recall the Associative Property of Addition: given three real numbers $a$ , $b$ and $c$ the following equality holds:

$(a+b) + c = a+(b+c)$ .

Let us remark that the Associative Property of Addition tells us that we can perform the sums in any order. So,

$(n+2)+7 = n+(2+7)$ .

In the other options there was used the Commutative Property of Addition.

6 0

3 years ago

Jennie charges $200 per passenger for a sunset sailing

Over [174]

Answer:

1692.5 and -232.5

Step-by-step explanation:

6 0

2 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

PLEASE! ANSWER THIS! HELP! PLEASE!!!!!!!!!!!!!! c. Expand: (tan(theta) - 1)^3

jonny [76]

Answer:

(tan(theta)-1)^3

= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)

= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)

= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1

= tan^3(theta)-3tan^2(theta)+3tan(theta)-1

Hope this helps :)

6 0

2 years ago