Question

find the height of a trapezoid with an area of 24 inches squared and bases with lengths of 16 and 8 in​

Answer 1

$\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel}\\ \qquad~ sides\\ h=heigh\\ \cline{1-1} A=24\\ a=16\\ b=8 \end{cases}\implies 24=\cfrac{h(16+8)}{2} \\\\\\ 24=\cfrac{24h}{2}\implies 48=24h\implies \cfrac{48}{24}=h\implies 2=h$