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ArbitrLikvidat [17]
2 years ago
7

What is the slope of a line with coordinates (5,3) and (1,2)? A (1,4) B 4 C (1,2)

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
8 0

Answer:

Slope (m) =

ΔY

ΔX

=

1

4

= 0.25

θ =  

arctan( ΔY ) + 180°

ΔX

= 194.03624346793°

ΔX = 1 – 5 = -4

ΔY = 2 – 3 = -1

Distance (d) = √ΔX2 + ΔY2 = √17 = 4.1231056256177

Equation of the line:

y = 0.25x + 1.75

or

y =  

1 x

4

+  7

4

When x=0, y = 1.75

When y=0, x = -7

Step-by-step explanation:

klasskru [66]2 years ago
3 0

Answer:

1/4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(2-3)/(1-5)

m=-1/-4

m=1/4

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Is 1.999 an irrational number
Roman55 [17]
Yes 1.999 is an <span>irrational number</span>
6 0
2 years ago
What is the radius of a circle given by the equation x2 + y2 – 2x + 8y – 47= 0?
miv72 [106K]

Answer:

8

Step-by-step explanation:

<h2 />
4 0
3 years ago
Read 2 more answers
In isosceles triangle ABC, AC=BC=20, the measure of angle A=68, and CD is the altitude to side AB. What is CD to the nearest 10t
antiseptic1488 [7]

Answer:

Step-by-step explanation:

Comment

The way the diagram looks when it is drawn is that you are going to need the sine function to solve for the side opposite which is CD.

Formula

Sin(A) = Sin(68 = opposite / hypotenuse     Substitute values.

Solution

sin(68) = altitude (side opposite) / 20       multiply both sides by 20

20*sin(68) = 20* altitude / 20                     substitute for sin(68)

20* 0.9272 = altitude

altitude = 18.5

Answer: 18.5 to the nearest tenth

3 0
1 year ago
A submarine is 730 m below sea level. An airplane that is directly over the submarine is 9,144 m above sea level. What is the ve
Rina8888 [55]
Submarine: -730
Airplane: 9,144
|-730-9,144|=|-9,874|=9,874
|d|: absolute value
The vertical distance between the submarine and airplane is 9,874 meters.
4 0
3 years ago
Read 2 more answers
Adrian exercised three days during the past week. He exercised 58 minutes and 45 seconds during the
aniked [119]

Answer:

2h 1' 1"

Step-by-step explanation:

1h = 1 hora

1' = 1 minute

1" = 1 secind

The sum of the three days is:

  58'  45"

+ 40'  40"

  20'  36"

= 118'  121"

118' 121" = 118' + 121"

1' = 60"

121" = 120" + 1"  = (120/60) + 1 = 2' + 1"

Then:

118' + 121" = 118' + 2' ´+ 1" = 120' + 1"

1 h = 60'

(120/60) + 1 = 2h + 1'

then:

118' + 121" = 2h + 1' + 1"

= 2h 1' 1"

3 0
1 year ago
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