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3 years ago

Which of the following best describes the folding method used to form an angle bisector?

2 answers:

8 0

The correct answer would be choice A.

An angle bisector is an angle that is exactly in the middle of an angle. It is right in between the two rays of the angle. If you fold a paper having the rays touch, the fold will be right in the middle. That will be your angle bisector.

arsen [322]3 years ago

6 0

Answer: A.

Step-by-step explanation: apex

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Describe how you can split a polygon in the shape of an L into smaller shapes.

11Alexandr11 [23.1K]

Split the L into separate shapes. To do this, where the bit sticks out, cut it off and deal with it separately.

7 0

3 years ago

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A cylinder is 20 inches long and has a diameter of 10 inches the approximate volume of the cylinder is_____ cubic centimeters

Lesechka [4]

Answer: 3987.8cm³

Step-by-step explanation:

Volume of a cylinder = πr²h

where

π = 3.14

r = diameter / 2 = 10in/2 = 5inches

h = height = 20in

Volume = πr²h

= 3.14 × 5² × 20

= 3.14 × 25 × 20

= 1570inches³

Since 1 inch = 2.54cm

1570 inch = (1570 × 2.54) = 3987.8cm³

Therefore, the volume of the cylinder is

3987.8cm³ cubic centimeters.

5 0

3 years ago

The US Pentagon is a regular pentagon whose outer walls are each 921 feet in length. Find the area, to the nearest square foot,

ziro4ka [17]

$\bf \qquad \qquad \textit{area of a regular polygon}
\\\\\\
A=\cfrac{1}{4}\cdot n\cdot s^2\cdot cot\left( \frac{180}{n} \right)\quad 
\begin{cases}
n=
\begin{array}{llll}
\textit{number of sides in a polygon}\\
\textit{a pentagon, has PENTA=5 sides}
\end{array}\\
s=\textit{length of one of the sides}
\end{cases}$

7 0

3 years ago

A random sample of 500 registered voters in Phoenix is asked if they favor the use of oxygenated fuels year-round to reduce air

Stells [14]

Answer:

a) 0.0853

b) 0.0000

Step-by-step explanation:

Parameters given stated that;

H₀ : p = 0.6

H₁ : p = 0.6, this explains the acceptance region as;

p° ≤ $\frac{315}{500}$ =0.63 and the region region as p°>0.63 (where p° is known as the sample proportion)

a).

the probability of type I error if exactly 60% is calculated as :

∝ = P (Reject H₀ | H₀ is true)

= P (p°>0.63 | p=0.6)

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p}{\sqrt{\frac{p(1-p)}{n}}} >\frac{0.63-p}{\sqrt{\frac{p(1-p)}{n}}} |p=0.6]$

= P $[\frac{p°-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} >\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500}}} ]$

= P $[Z>\frac{0.63-0.6}{\sqrt{\frac{0.6(1-0.6)}{500} } } ]$

= P [Z > 1.37]

= 1 - P [Z ≤ 1.37]

= 1 - Ф (1.37)

= 1 - 0.914657 ( from Cumulative Standard Normal Distribution Table)

≅ 0.0853

The probability of Type II error β is stated as:

β = P (Accept H₀ | H₁ is true)

= P [p° ≤ 0.63 | p = 0.75]

where p° is represented as pI in the subsequent calculated steps below

= P $[\frac{p°-p} \sqrt{\frac{p(1-p)}{n} } }\leq \frac{0.63-p}{\sqrt{\frac{p(1-p)}{n} } } | p=0.75]$

= P $[\frac{p°-0.6} \sqrt{\frac{0.75(1-0.75)}{500} } }\leq \frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P $[Z\leq\frac{0.63-0.75}{\sqrt{\frac{0.75(1-0.75)}{500} } } ]$

= P [Z ≤ -6.20]

= Ф (-6.20)

≅ 0.0000 (from Cumulative Standard Normal Distribution Table).

6 0

3 years ago

Describe how the graph is like the graph of y = |x| and how it is different.

Tasya [4]

Check the picture below.

the black graph is and |x| are both "similar" or the same shape, however |x| has a y-intercept at the origin, whilst the black graph has it at y = -7.

4 0

4 years ago

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