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ZanzabumX [31]
3 years ago
14

A similarity ratio is the ratio of the lengths

Mathematics
1 answer:
kow [346]3 years ago
7 0
Similarity ratio is a ratio of two figures having the same side.

Ratio can be rate but rate can never be ratio. In essence, rate is comparison between ratios.  While ratio is comparison between two or more numbers. Further, ratio on one hand, involves numbers either in amount, size, measurement, degrees, percentages or fractions with the absence of specific unit of measurement. On the contrary, rate is comparing quantities, amounts or unit of events happened expressed in a specific measurement or expressed under time. Take for instance, an example, Joe eats 2 while John eats 4 meals in a day. The ratio can be Joe: John, 2:4 meals. While the rate, is Joe eats 2 meals/day and John 4 meals/day.<span>
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-5.5x+0.56= -1.64 What does x equal to ?
RUDIKE [14]
-5.5x+0.56= -1.64 -0.56 -0.56 -5.5x= -2.2 /5.5 /5.5 x= -0.4 is the answer
5 0
3 years ago
The following graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k:
hoa [83]
B is the correct answer
4 0
3 years ago
According to records from 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the probabil
Brrunno [24]

Record of june temperature of last 50 years

Probability of June temperature being above 80° F from last 50 years

                      =\frac{2}{3}

It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

                =\frac{20+x}{30}  

where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

                \frac{2}{3}\leq P \leq 1  

Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

Total number of numbers on number cube ={1,2,3,4,5,6}

Favorable Outcome={1,2,3,4}=Temperature above 80° F

Temperature 80° F or below ={5,6}

⇒Probability of getting number {1,2,3,4} on the number cube when rolled once,that is Temperature above 80° F

        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

4 0
3 years ago
I dont really understand this
galina1969 [7]

Answer:

1. a^-b

2.a^b/a^c

3.a^c/b^c

4 0
3 years ago
Please show me the steps of 78.32/0.22
spayn [35]
78.32/0.22= 356

Divide

____
0.22/ 78.32
7 0
3 years ago
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