Answer:
Before meiosis actually begins, the DNA that is packaged into chromosomes must be fully copied.
Answer:
Point 3 for kinetic, points 1 and 5 for potential
Explanation:
There is one point that the ball has the most kinetic energy it is at point 3. Point 3 has the most kinetic energy because it has gained the most speed since it was dropped and it also is right before it starts slowing down from trying to go up again. Points 1 and 5 have the most potential energy. When the ball is at point 1 or 5 it is at its maximum height thus it cannot swing any further, so it stops for a split second and gains a large amount of potential energy before it is released into kinetic energy when it falls back down.
“The nth term of the following types of sequences can be found out using the following Formulas:
1.Arithmetic Progression(AP) : here, the consecutive terms differ by a common difference (d).
tn= a+(n-1)d
Where,
a= is the first term of the sequence,
n= nth term
d= common difference
2. Geometric Progression(GP):
Here, the consequtive terms differ by a common ratio (r).
Tn= ar^(n-1)
where,
a = first term
r = common ratio
tn= nth term
3.Harmonic Progression (H.P):
It is the reciprocal of AP.
To find nth term of a HP, first convert it into AP and then apply the tn formula for the sequence and take the reciprocal of the obtained tn again.
Hope the answer helps you!!”
They survive without water by entering a special mode, otherwise called as shriveling. They can lose even 95% of water in their body and still live, even though they would look like dead plants, they would actually be alive. In the absence of water, tardigrades use a sugar called trehalose, which becomes their source of life until they find some water.
Answer:
Option A is the correct answer. To conduct a controlled experiment would be the best choice for Maria to test her prediction.
Explanation:
A controlled experiment can be described as an test in which one of the test models is kept constant for a variable, while in other experimental models, a change is made for testing the variable.
It would be best for Maria to conduct a controlled experiment. In the control model, Maria should keep light as constant whereas in other experimental models she should increase and decrease the quality of light to test her prediction. She should then compare her experimental results with the control model to deduce the results.
