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Dimas [21]
3 years ago
6

A teacher attaches a ball to a meter long string and whirls it around in a horizontal circle at constant speed. The teacher expl

ains that the string is what makes the ball go in a circle. Why is the string necessary? A) The string is needed to apply a torque to the ball. B) The string is needed to push on the ball to get it up to speed. C) Circle motion requires an inertia which is provided by the string. D) Circle motion requires a force to give it a centripetal acceleratio
SAT
2 answers:
Agata [3.3K]3 years ago
7 0

To whirl any object in a circle, the most necessary factors are a force and a perpendicular distance about its centre.

And the product of these two factors gives torque i.e torque= force × perpendicular distance.

Hence A is the correct answer.

Yuliya22 [10]3 years ago
5 0

The string is needed to apply a torque to the ball.

Answer: Option A

<u>Explanation:</u>

To rotate any object in a circle, the most important factors are force and perpendicular distance around the center. The product of these two factors produces torque, i.e. Forces x vertical distance. An object moving in a circle must exert an internal force to achieve internal acceleration.

In this case, the string is needed for the ball to rotate, because that makes the ball go in a circle. This is done by dragging the object to the center of the circle.

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Answer: The ACT is a standardized test that measures a student's skills in five core areas: English, math, reading, science, and writing (optional). Students in grades 11 and 12 take the ACT so that they can submit their scores to colleges as part of the college application process. 75 questions in 45 min.

4 0
3 years ago
Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

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k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

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Answer:

[See Below]

Explanation:

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✦ Abstemious - Moderate in eating and drinking.  

✦ Repose - State of rest.

✦ Omnivorous - Eating any kind of food.

✦ Disparate - Different.

✦ Redolent - Nice smelling.

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2.)

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