Answer:
3
Step-by-step explanation:
y=2/2
y=1
1+?=4
1+3=4
Answer:
it depends (see below)
Step-by-step explanation:
<u>Exact Interest</u>
Exact interest is calculated on the basis of a 365-day year, so the exact interest on the loan would be ...
I = Prt = $7500·0.10·(85/365) = $174.66
Then the proceeds would be ...
$7500 -174.66 = $7,325.34 . . . . . matches first option
__
<u>Ordinary Interest</u>
Exact interest is calculated on the basis of a 360-day year, so the ordinary interest on the loan would be ...
I = Prt = $7500·0.10·(85/360) = $177.08
Then the proceeds would be ...
$7500 - 177.08 = $7,322.92 . . . . . matches last option
_____
I suggest you check your reference materials (text or course examples) to see what year length is expected to be used in this calculation. Some on-line references show it one way; others show it the other way.
Answer:
please correct me if im wrong but i got 82,800 as the answer to this.
Step-by-step explanation:
Answer:
18.85
Step-by-step explanation:
So the circumference of a circle = 2πr
if the diameter is 6, then the radius is 3.
so 2π(3)
= 6π
= 18.85 units of measurement
Answer:
Step-by-step explanation:
First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.
If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.
After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form
y = ±
Filling in our asymptotes as they were given to us:
y = ±
where a is 2 and b is 1. Now we can write the formula for the hyperbola!:
which of course simplifies to
