Answer:
The Volume of large cone is 19.545 greater than the smaller cone
Step-by-step explanation:
Given:
Size of the small cone = 3.5 inches
Diameter of the small cone = 3 inches
Size of the large cone = 3.5 inches
Diameter of the small cone = 3 inches
To Find:
How much greater, to the nearest tenth of a cubic inch, is the volume of the larger cone than the volume of the smaller cone = ?
Solution:
Volume of the small cone :
Radius =
Radius =
Radius = 1.5 inches
volume of the cone =
substituting the values,
=>
=>
=> 16.485
Volume of the large cone :
Volume of the large cone :
Radius =
Radius =
Radius = 2.25 inches
volume of the cone =
substituting the values,
=>
=>
=>36.06
Now ,
volume of small cone - volume of large cone
=>36.06 - 16.485
=>19.545
Answer:
I'm pretty sure the answer is b
Answer:
Step-by-step explanation:
the arc length is equal to the radius x angle (in radians)
s= arc length, r= radius and a= the angle
solve for a ; a= s/r; a=
Answer:
B 2
Step-by-step explanation:
The computation of the value of f(x) in the case when x = 2 is shown below
As per the question, following function is given
F(x) = (1 ÷ x) + 2
Based on this, the x = 2
Now put the x value in the above equation
So,
= (1 ÷ 2) + 2
= (1 + 4) ÷ 2
= 5 ÷ 2
= 2.5
Hence the closet number is 2
Therefore the value of f(x) in the case when x = 2 is 2
Hence, the correct option is b.