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masha68 [24]
3 years ago
14

HELP!!!! NEED ANSWER ASAP!

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

Answer:

yes, its more than 600$ the answer is 700$ good luck and tell me if u got this right or wrong (if it's wrong, I'm sorry)

You might be interested in
How many times greater is 36 than 33
masya89 [10]

Answer:

1 1/11 times greater

Step-by-step explanation:

When we are looking for how man time greater, we know we have to divide

36/33

Each number can be divided by 3

12/11

We can change this to a mixed number

1 1/11 times greater

6 0
3 years ago
I need help please help me
harkovskaia [24]
We substitute in c using 9, it will be as follows:
5 ×[(-6×9)+4] = 5 × (-54+4) = 5 × (-50) = -250
3 0
3 years ago
Marle placed two orders at the same restaurant last month. In one order, she received 5 trays of lasagna and 3 trays of
user100 [1]

Answer:

$25.25-lasagna, $12.25-garlic bread

Step-by-step explanation:

  5L+3G=163

- 4L+4G=150

______________

 4(5L+3G=163)

-5(4L+4G=150)

_____________

20L+12G=652

-20L-20G=-750

_____________

          -8G=-98

         -8G/-8 = -98/-8

               G=$12.25

now plug that into G in any of the 2 equations at the top and you can solve for L(price of lasagna)

5 0
3 years ago
Can I get a help please ​
iogann1982 [59]

Answer:

middle graph

Step-by-step explanation:

Soluton

The  second (middle ) graph is the only one that works.

  • First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ -  1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
  • Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.

6 0
2 years ago
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
3 years ago
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