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2 years ago

Write the ratio as a fraction in simplest form. 3 ft to 7 yd

Mathematics

1 answer:

jolli1 [7]2 years ago

4 0

Its going to be 3/7 because 3 is the first number and 7 is the second

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Henry makes $7.00 per hour before taxes working at a movie theater. On Tuesday, Henry worked 5 hours, and then he worked 4 hours

olganol [36]

Answer:

Step-by-step explanation:

1hr = $7.00

Therefore,

5 + 4 x 7

= $63

DV = Hours of work.

7 0

2 years ago

Rob is saving to buy a new MP3 player. For every $13 he earns babysitting, he saves $9. On Saturday, Rob earned $78 babysitting.

stealth61 [152]

Answer:

54$

Step-by-step explanation:

We know that for each 13$ Rob earns babysitting, he saves 9$. Thus, we can separate the money he earns into groups of 13, and for each group of 13, we can add 9$ to his savings.

Assume that Rob has 78$ lying on a table. He grabs 13 of them, leaving 65, and puts 9$ to the side for savings. He does this 5 more times (as 65 divided by 13 is 5, so Rob would make 5 groups of 13 out of his 65$ that is left), meaning that he now has 5+1 (the original group) = 6 groups of 9. 9*6=54, so he saves 54$. Please let me know if you have any further questions!

7 0

3 years ago

Help me please!!!!!! giving out brainliest

vazorg [7]

Answer:

1 = 175ft cubed

2 = 58m cubed

3 = 140m cubed

4 = 180in cubed

Step-by-step explanation:

You have to split these complex shapes into parts and find the volume of each part. Then, add the parts' volumes together, which will be the total volume of these. The equation is V=bhw. V means volume, b means base, h means height, and w means width. Hope this helps!

6 0

2 years ago

Best answer dets Brainliest!!!

Gala2k [10]

Plot the points at
(-9,-5)
And
(-3,-5)
This looks right

8 0

2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago