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Ierofanga [76]
3 years ago
9

Write the ratio as a fraction in simplest form. 3 ft to 7 yd

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0
Its going to be 3/7 because 3 is the first number and 7 is the second
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Write an explicit formula for the recursive formula <br><br> A(n) = A(n - 1) + 3; A(1) = 6
arsen [322]

Answer:

a_{n} = 3n + 3

Step-by-step explanation:

The sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

From the recursive formula

a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then

a_{n} = 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3

7 0
2 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
PLEASE HELP ATTACHED BELOW
ddd [48]
I’m not sure but i think it is 126 pi IM SORRY IF IM WRONGGGGG
6 0
2 years ago
Which choice is equivalent to the product below when x&gt;0?
V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }

\sqrt{a\\} × \sqrt{b} ⇔ \sqrt{ab}

Given

\sqrt{\frac{6}{x} } × \sqrt{\frac{x^2}{24} }

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x^2}{24}

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x}{2 \sqrt{6\\} }

Cancel \sqrt{6} on numerator/ denominator

= \frac{1}{\sqrt{x} } × \frac{x}{2\\}

= \frac{1}{\sqrt{x} } × \frac{(\sqrt{x})^2 }{2}

Cancel \sqrt{x} on numerator/ denominator, leaving

= \frac{\sqrt{x} }{2} → D

4 0
3 years ago
If a= -2, y = -3 and z = 4, find the values of the following algebraic expressions. -3az
kipiarov [429]

Answer:

24

Step-by-step explanation:

substitute the given values for a and z into the expression

- 3az

= - 3(- 2)(4) = 6 × 4 = 24

5 0
2 years ago
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