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vaieri [72.5K]
3 years ago
15

Simplify the given equation 5x+2(x-3)=-2(x-1)

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

Answer:

x =8/9 i dont know if im correct

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Find the value of x please and thank you
Pachacha [2.7K]

Given:

In triangle DEF, HG is parallel to DF.

To find:

The value of x.

Solution:

In triangles DEF and GEH,

\angle DE F\cong \angle GEH          (Common angle)

\angle EDF\cong \angle EGH          (Corresponding angle)

\Delta DE F\sim \Delta GEH             (By AA property of similarity)

We know that corresponding sides of similar triangle are proportional.

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\dfrac{9+(x+5)}{x+5}=\dfrac{12}{6}

\dfrac{x+14}{x+5}=2

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x+14=2x+10

Isolating variable terms, we get

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Therefore, the value of x is equal to 4.

3 0
2 years ago
An exponent is also called___.
bija089 [108]

Answer:

An expression that represents repeated multiplication of the same factor is called a power.

Step-by-step explanation:

The number 5 is called the base, and the number 2 is called the exponent. The exponent corresponds to the number of times the base is used as a factor.

8 0
3 years ago
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
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