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Vinvika [58]
4 years ago
15

The middle school is 2.72 km from Marsha's house and 1.54 km from Ryan's house. How much farther does Marsha live from the middl

e school then Ryan
Mathematics
1 answer:
AlladinOne [14]4 years ago
3 0
Ryan lives 1.54 km from middle school
Marsha lives 2.72 km from middle school

2.72 - 1.54 = 1.18....Marsha lives 1.18 km further 
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Joseph buy the CD that cost $18. she handed the clerk d dollars. she received more than $30 in change. Which inequality best rep
dimaraw [331]
C

She'd have to have given her more than 48 dollars to receive more than 30 dollars back

It can't be D because that implies she could've received exactly 30 dollars in change and the question states she received more than that.

8 0
4 years ago
What is the answer?
arsen [322]
10 equal pieces I think
6 0
4 years ago
(a) Although neither a linear nor an exponential function would model this data perfectly, justify why an
Alinara [238K]

Answer:

hello the table related to this question is missing attached below is the missing table

answer : An exponential function is much better fit because there is no fixed rate in the table

Step-by-step explanation:

An exponential function is much better fit because there is no fixed rate in the table attached but the values in the table keeps increasing exponentially, hence an Exponential function will be a better fit, But a linear function would be preferred only if there is a fixed rate

7 0
3 years ago
Help please? I’m not so intelligent.
nlexa [21]

Answer:

It is 33. Answer B is correct.

5 0
3 years ago
N=4; 2i and 3i are zeros <br> f(-1)=50
Nonamiya [84]

Solution:- \text{Let f(x) be any nth degree polynomial with n=4}\\

\text{Given that 2i and 3i are the zeroes of f(x)}

\text{so (x-2i) and (x-3i) are factors of f(x)}

\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}

\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)

6 0
3 years ago
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