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SpyIntel [72]
3 years ago
5

Explain how the following inequality can be used to find the number of toys you can afford to buy. 150≤ 11x + 10 ≤ 450

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

The maximum number of toys you can afford to buy is 40

Step-by-step explanation:

Let

x -----> the number of toys

we have the compound inequality

150\leq 11x+10\leq 450

Divide into two inequalities

150\leq 11x+10 -----> inequality A

11x+10\leq 450 ----> inequality B

<em>Solve the inequality A</em>

150-10\leq 11x

140\leq 11x

Divide by 11 both sides

12.7\leq x

Rewrite

x\geq 12.7

<em>Solve the inequality B</em>

11x\leq 450-10

11x\leq 440

Divide by 11 both sides

x\leq 40

The solution for x is the interval  ----> [13,40}

Remember that the number of toys must be a whole number

The domain is all whole numbers greater than or equal to 13 toys and less than or equal to 40 toys

therefore

The maximum number of toys you can afford to buy is 40

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1 inch is 6 feet.

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Shane has a garden box that is 4 feet long, 4 feet wide, and foot deep.
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How much soil for a raised bed?

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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

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Answer:

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Step-by-step explanation:

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