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3 years ago

3.2x3 + 4.8x +3.7 2.1x3 +6.3x - 2.9

Mathematics

2 answers:

inna [77]3 years ago

8 0

Answer:

5.3x^3+11.1x+0.8

Step-by-step explanation:

Add ones with similar variables

5.3x^3+11.1x+0.8

worty [1.4K]3 years ago

6 0

Answer: 5.3x^3 + 11.1x + 0.8

I hope this helps! :)

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Evaluate √81/√9<br> help lolll

just olya [345]

Answer:

Step-by-step explanation:

$\sqrt{81}=9\\\sqrt{9}=3\\therefore 9x3=27$

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3 years ago

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9 times (30+7=(9 times _)+(9 times 7)<br><img src="https://tex.z-dn.net/?f=9%20%5Ctimes%20%2830%20%2B%207%29%20%3D%20%289%20%5Ct

Arada [10]

9(30+7) = (9*30)+(9*7)

This is the distributive property

x(y+z) = xy + xz

Let the dash = x

9(30+7) = (9*x)+(9*7)

9(37) = 9x + 63

333 = 9x + 63

Substract 63 from both sides

333 - 63 = 9x +63-63

270 = 9x

Divide both sides by 9

270/9 = 9x/9

30 = x

Or x = 30

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3 years ago

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Find the perimeter of this please help.

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Answer:

i think the perimeter is 17 hope this helps

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3 years ago

Estimate the products of 79 × 37 and 62 × 49 . Which choice shows the sum of the estimates?

klio [65]

Answer:

Sue of estimates = 6200

Step-by-step explanation:

$79\times37$ can be estimated as $80\times 40$ which is $=3200$

Similarly $62\times49$ can be estimated as $60\times 50$ which is $=3000$

∴ Sum of estimates = $3200+3000=6200$

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3 years ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

gulaghasi [49]

Answer: $P(A\cap B)=\frac{1}{3}$

$P(A)=\frac{1}{3}$

$P(B)=1$

$P(A|B)=\frac{1}{3}$

Step-by-step explanation:

From the given figure it can be seen that

Total number on cube= n(S)=6

Intersection of A and B = n(A ∩ B)= 2

Therefore,

$P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}$

Also, The number of elements in A = 2

Therefore,

$P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}$

Similarly, The number of elements in B= 6

Therefore,

$P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1$

The formula to find the conditional probability is given by :-

$P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}$

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4 years ago

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