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AfilCa [17]
3 years ago
11

Stan drove for h hours at a constant rate of r miles per hour. How many miles did he cover during the final 20 minutes of his dr

ive?
Mathematics
2 answers:
valentinak56 [21]3 years ago
6 0

r multiplied by 1/5h

expeople1 [14]3 years ago
3 0

Answer:

r/3

Step-by-step explanation:

Its right

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Help please !! Thank u
leonid [27]

Answer:

parallel = same slope (-2x)

so it's y=-2x + b

let's find b by plugging in 1 for x and 3 for y (the coordinates)

3 = -2*1 + b

3 = -2 + b

5 = b

there you have it:

y = -2x +5

brainliest would really be appropriated (possible when someone else also leaves an answer)

4 0
3 years ago
2(-3a+5)=-4(a+4)<br>helps plzs!!!!.....​
Nana76 [90]
-6a+10=-4a-16
-6a+26=-4a
26=2a
A=13
8 0
3 years ago
There are 50 campers at day camp and 10 counselors. Write the ratio of campers to counselor as a fraction . Explain how to use e
nadezda [96]
Take the common denominator and divide by 3 then youll get 58
4 0
3 years ago
Find the angle of elevation of the sun when a 12.5 meter tall telephone pole casts an 18 meter
MAVERICK [17]
To answer this problem, you should know the formula that we will be using and this would be:
Angle of elevation = arc tan( (vertical height)/(length of the shadow)).

Plugging in the values in the formula. Here, this angle is:

arc tan (12.5/18) = <span>34.78 degrees</span>

The answer would be approximately 34.78 degrees

3 0
3 years ago
Need the a answer for this
FinnZ [79.3K]

Answer:

Given expression:

\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}

Separate the variables:

\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}

Reduce the first fraction:

\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}

\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}

\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}

\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}

\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}

Therefore:

\implies \dfrac{7a^6b^3}{4c^5}

4 0
1 year ago
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