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Gala2k [10]
2 years ago
7

A Triangular prism with a triangular base of 8 in. and height of 6in. and a prism height of 4in. What is the surface area of the

prism
Mathematics
1 answer:
Minchanka [31]2 years ago
3 0
I think the answer would be 8 in.... does it have any anser choices? 
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The table below shows the sample space for spinning a 4-part spinner (labeled A, B, C, D) and then a 5-part spinner (labeled V,
Kipish [7]
2/9 i think im noy sure
8 0
3 years ago
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Please help ill give you. brainiest
Bond [772]

I believe the answer is b

3 0
3 years ago
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The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar
o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

  • The combined area of two squares = 80 sq.cm
  • The side of small square = x
  • The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

x^2 = 16

x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

5 0
3 years ago
PLEASE HELP (100 POINTS)
Artyom0805 [142]

\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5

Compare to standard equation of SHM

\\ \rm\Rrightarrow y=Acos(\omega x+\phi)

Here

  • Amplitude=A=-5

\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}

\\ \rm\Rrightarrow \omega=1/2

Well the above one are for extra knowledge .

Solution:-

\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5

\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}

\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1

\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)

\\ \rm\Rrightarrow \dfrac{x}{2}=\pi

\\ \rm\Rrightarrow x=2\pi

So.

\\ \rm\Rrightarrow x=2\pi+2\pi n

3 0
2 years ago
Read 2 more answers
The mean of five numbers is 8. when another number is added the mean is 7. find the number added
sasho [114]

Answer:

\large \boxed{\sf \ \ 2  \ \ }

Step-by-step explanation:

Hello,

<u>The mean of five numbers is 8</u> so we can write

\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8

<u>When another number is added the mean is 7</u>, let s note x the another number we can write

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7

From the first equation we can say

x_1+x_2+x_3+x_4+x_5=8*5=40

So the second equation becomes

\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\ \dfrac{40+x}{6}=7\\\\40 + x = 6*7=42\\\\ x = 42-40 = 2\\

The solution is then 2

Hope this helps

4 0
2 years ago
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