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2 years ago

7

A Triangular prism with a triangular base of 8 in. and height of 6in. and a prism height of 4in. What is the surface area of the

prism

1 answer:

Minchanka [31]2 years ago

3 0

I think the answer would be 8 in.... does it have any anser choices?

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The table below shows the sample space for spinning a 4-part spinner (labeled A, B, C, D) and then a 5-part spinner (labeled V,

Kipish [7]

2/9 i think im noy sure

8 0

3 years ago

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Please help ill give you. brainiest

Bond [772]

I believe the answer is b

3 0

3 years ago

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The combined area of two squares is 80 square centimeters. Each side of one square is twice as long as a side of the other squar

o-na [289]

The length of each side of the larger square is 8 cm.

<u>Step-by-step explanation</u>:

Step 1 ;

The combined area of two squares = 80 sq.cm
The side of small square = x
The side of larger square = 2x

Step 2 :

Area of the square = a^2

Area of small square + area of large square = 80

x^2 + (2x)^2 = 80

x^2 + 4x^2 = 80

5x^2 = 80

x^2 = 80/5

x^2 = 16

x = ±4

Step 3 :

Since length cannot be negative, the value of x= 4

∴ The length of the side of small square = 4cm

The length of the side of larger square = 2x = 8cm

5 0

3 years ago

PLEASE HELP (100 POINTS)

Artyom0805 [142]

$\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5$

Compare to standard equation of SHM

$\\ \rm\Rrightarrow y=Acos(\omega x+\phi)$

Here

Amplitude=A=-5

$\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}$

$\\ \rm\Rrightarrow \omega=1/2$

Well the above one are for extra knowledge .

Solution:-

$\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5$

$\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1$

$\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)$

$\\ \rm\Rrightarrow \dfrac{x}{2}=\pi$

$\\ \rm\Rrightarrow x=2\pi$

So.

$\\ \rm\Rrightarrow x=2\pi+2\pi n$

3 0

2 years ago

Read 2 more answers

The mean of five numbers is 8. when another number is added the mean is 7. find the number added

sasho [114]

Answer:

$\large \boxed{\sf \ \ 2 \ \ }$

Step-by-step explanation:

Hello,

<u>The mean of five numbers is 8</u> so we can write

$\dfrac{x_1+x_2+x_3+x_4+x_5}{5}=8$

<u>When another number is added the mean is 7</u>, let s note x the another number we can write

$\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7$

From the first equation we can say

$x_1+x_2+x_3+x_4+x_5=8*5=40$

So the second equation becomes

$\dfrac{x_1+x_2+x_3+x_4+x_5+x}{6}=7\\\\ \dfrac{40+x}{6}=7\\\\40 + x = 6*7=42\\\\ x = 42-40 = 2\\$

The solution is then 2

Hope this helps

4 0

2 years ago