Answer:
all positive inegers
Step-by-step explanation:
Answer:
603
Step-by-step explanation:
The rate of change is found by
rate of change = f(b) -f(a)
------------
b-a
We need to find the rate of change for the interval 7,9 and 4,6
We know b= 9 and a = 7
f(9) -f(7)
------------
9-7
3878-1852
----------------
9-7
2026
-------
2
1013
We know b= 6 and a = 4
f(6) -f(4)
------------
6-4
1178-358
---------------
6-4
820
------
2
410
It asks how much greater, that means subtraction
1013-410
603
Answer:
(c) 2.034 s; (d) 8.944 cm
Step-by-step explanation:
Velocity and acceleration
s = 8cos(t) + 4sin(t)
v = -8sin(t) + 4cos(t)
a = -8cos(t) + 4sin(t)
(c) Time to first equilibrium position
The equilibrium position is where the mass hangs before it is pulled downward, that is, at s = 0.
Set s = 0 and solve for t.
If n = 1,
t = -1.107 + π = 2.034 s
(d) Distance from equilibrium position
The mass will reach its maximum distance when v = 0, that is, when it is at the peak or trough of its oscillation.
Set v = 0 and solve for t.
If n = 0,
t = 0.4636
Then
s = 8cos(0.4636) + 4sin(0.4636) = 8×0.8944 + 4×0.4472 = 7.156 + 1.789 = 8.944 cm
The figure below shows the graphs of s and v vs t. They indicate that the mass first reaches its equilibrium position at 2.034 s, and the amplitude of its vibration is 8.944 cm.
Here's the one with whole numbers:
[8] [1] [6]
[3] [5] [7]
[4] [9] [2]
For the one with polynomials, all you have to do it pick any weird number
you want for 'x', and then translate the whole numbers into expressions
with 'x' in them.
For example, if you say that 'x' is 1.6 . . . just a wild pick. Then ...
1 = x - 0.6
2 = x + 0.4
3 = 2x - 0.2
and so forth, and you could fill these into the second magic square
in place of the whole numbers.
Or if you don't want to mess with all the decimals, then just pick
a whole number for 'x'. I don't know ... maybe ' 4 '. Then ...
1 = x -3
2 = -x + 6
3 = (1/2)x + 1
and so forth. You just pick any old number you want for 'x',
and then make up expressions with it to substitute for all the
whole numbers in the first magic square.