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faust18 [17]
3 years ago
7

PLZ HELP ME I BEG U 50 pints

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0

Answer:

Solution given;

perimeter of triangle=20+20+24=64mm

height of triangle =16mm

length of rectangle=23mm

breadth of rectangle=24mm

we have

Total surface area=perimeter of triangle *length + 2*area of rectangle

=64*23+2*23*24=2576mm²

S<u>u</u><u>r</u><u>f</u><u>a</u><u>c</u><u>e</u><u> </u><u>area</u><u>=</u><u>2576mm²</u>

yarga [219]3 years ago
3 0

Answer:

1496.79 mm squared

Step-by-step explanation:

Have a good day :)

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Alina and Asim share Rs 210 in the ratio 2:5. How much money did each of them get?
slavikrds [6]

Answer:

Step-by-step explanation:

Alina=2x---eq(1)

Asim=5x----eq---(2)

So,we get

2x+5x=210

7x=210

x=30

Now,Putting '30' in eq 1 and eq 2

2*30=60

5*30=150

Therefore Alina got 60 Rs while Asim got 150 Rs

5 0
3 years ago
Huilan is 15 years younger than Thomas. The sum of their ages is 33 . What is Thomas's age?
Sphinxa [80]

h = t - 15

h + t = 33

Because we have a value of h, we can plug it into the second equation to solve for t.

t - 15 + t = 33

Add 15 to both sides.

t + t = 48

Combine like terms.

2t = 48

Divide both sides by 2.

t = 24

<h3>Thomas's age is 24.</h3>
6 0
3 years ago
Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.
jeka94

Answer:

x=4+2\sqrt{3}

x=4-2\sqrt{3}

Step-by-step explanation:

<u>Completing the square</u>

when  ax^2+bx+c=0

Given equation:

3x^2-24x+40=28

Subtract 40 from both sides:

\implies 3x^2-24x=-12

Divide both sides by 3:

\implies x^2-8x=-4

Add the square of half the coefficient of x to both sides:

(\frac{b}{2})^2=(\frac{-8}{2})^2=16

\implies x^2-8x+16=-4+16

Factor the left side and simplify the right side:

\implies (x-4)^2=12

Square root both sides:

\implies x-4=\pm\sqrt{12}

Add 4 to both sides and simplify the radical:

\implies x=4\pm\sqrt{4 \cdot 3}

\implies x=4\pm\sqrt{4}\sqrt{3}

\implies x=4\pm2\sqrt{3}

5 0
1 year ago
Find the surface area of the cube shown.
Alja [10]

A=6a^2

A=6(5.5)^2

A=181.5

Hopefully I answered correctly.

8 0
3 years ago
Read 2 more answers
Solve the following equation. X cubed minus 6X squared plus 6X equals zero
anyanavicka [17]

We have to solve this equation:

x^3-6x^2+6x=0

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}

Now we can find the roots of the quadratic polynomial as:

\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0
1 year ago
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