The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
71290 because the ones are 0 and zero is lower than 5
so it wouldn't add anything to the tens
the rule is if the number is more than 5+ it will add 1 to the next number
for example if we have this number 189 and we want to round it to the nearest 10 ..
we will see the ones place is it more than 5+ ? YEAH bcz its 9 ...
so 9 will add one to the tense and the answer will be 190 :)
hope you got the point .
Answer:
201
Step-by-step explanation:
Answer: 64 units
Step-by-step explanation:
Remember, the formula to find surface area given radius is . Let's add in the given information:
4pi4^2 =
4pi16
64pi!
Hope this helps, please consider making me Brainliest.
Answer:
See the proof below
Step-by-step explanation:
Let the line AB be a straight line on the parallelogram.
A dissection of the line (using the perpendicular line X) gives:
AY ≅ BX
Another way will be using the angles.
The angles are equal - vertically opposite angles
Hence the line AY ≅ BX (Proved)