Answer:
Clastic sedimentary rocks are made up of pieces (clasts) of pre-existing rocks. Pieces of rock are loosened by weathering, then transported to some basin or depression where sediment is trapped. If the sediment is buried deeply, it becomes compacted and cemented, forming sedimentary rock.
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Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent composition of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Answer:
P₂ = 1.92 atm
Explanation:
According to the boyle's law:
The pressure of given amount of gas at constant temperature and number of moles of gas is inversely proportional to the volume.
P₁V₁= P₂V₂
Given data:
Initial volume = 4.00 L
Initial pressure = 1.20 atm
Final volume = 2500 mL
Final pressure = ?
Solution:
First of all we will convert the volume into litter.
2500 mL × 1L/1000 mL = 2.5 L
P₁V₁ = P₂V₂
P₂ = P₁V₁ /V₂
1.20 atm×4.00 L = P₂ ×2.5 L
P₂ = 1.20 atm×4.00 L/ 2.5 L
P₂ = 4.8 atm. L/ 2.5 L
P₂ = 1.92 atm