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Vikentia [17]
3 years ago
10

Carbon dioxide (CO2) is a gas at room temperature and pressure. However, carbon dioxide can be put under pressure to become a "s

upercritical fluid" that is a much safer dry-cleaning agent than tetrachloroethylene. At a certain pressure, the density of supercritical CO2 is 0.469 g/cm3. What is the mass of a 25.0-mL sample of supercritical CO2 at this pressure?
Chemistry
1 answer:
Lunna [17]3 years ago
5 0

Answer:

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

Explanation:

Step 1: Given data

The supercritical CO2 has a density of 0.469 g/cm³ (or 0.469 g/mL)

The sample hasa volume of 25.0 mL

Step 2: Calculating mass of the sample

The density is the mass per amount of volume

0.469g/cm³ = 0.469g/ml

The mass for a sample of 25.0 mL = 0.469g/mL * 25.0 mL = 11.725g ≈ 11.7g

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

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What is the density of laughing gas, dinitrogen monoxide, n2o, at a temperature of 325 k and a pressure of 113.0 kpa?
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<em>Answer :</em> the density of the N₂O at 325 K and 113.0 kPa  is 1.84 kg m⁻³.

<span>
<span><em>Explanation : </em>

Density (kg/m³) = mass (kg) / Volume (m³)
</span><span> <span>d = m/V                 (1)

Ideal gas law,
PV = nRT               (2)</span></span></span>

<span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span>⁻¹ K⁻<span>¹) and T is temperature in Kelvin.

n = m/M          (3)

Where, n is number of moles, m is mass and M is molar mass.

From (2) and (3),
PV = (m/M) RT

By rearranging,
P = (m/VM)RT              (4)

From (1) and (4)
P = (dRT) / M

The given data,
P = 113.0 kPa = 113.0 x 10</span>³ Pa<span>
d = ?
R = 8.314 J mol</span>⁻¹ K⁻<span>¹
T = 325 K 
M = </span>44.0 g/mol  = 44.0 x 10⁻³ kg/mol

<span>
By substitution,</span>

113.0 x 10³ Pa = (d x 8.314 J mol⁻¹ K⁻¹ x 325 K) / 44.0 x 10⁻³ kg/mol

             d = (113.0 x 10³ Pa x 44.0 x 10⁻³ kg/mol) / (8.314 J mol⁻¹ K⁻¹ x 325 K<span>)
             d = 1.84 kg m</span>⁻<span>³

Hence, the density of the N</span>₂O at 325 K and 113.0 kPa is 1.84 kg m⁻³.

<span>
Assumption made is "N</span>₂O gas has an ideal gas behavior".

 

6 0
3 years ago
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