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4 years ago

What is the mode of the following numbers? 6 , 4 , 1 , 9 , 3 , 8 , 3 , 5 , 10

Mathematics

1 answer:

laiz [17]4 years ago

3 0

List the numbers from least to greatest:

1, 3, 3, 4, 5, 6, 8, 9, 10

Mode: ( most number repeated in the list)

Mode: 3

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If the original quantity is 8 and the new quantity is ,2 what is the percent decrease?

azamat

Answer: 75%

Step-by-step explanation:

75% of 8 is 6.

8 was decreased by 6 to get 2.

8 was decreased by 75% of its initial value to get 2.

Hope this helped!

3 0

3 years ago

Read 2 more answers

Find the perimeter of the quadrilateral that has vertices at (8,13), (5,-18), (-6,-6), and (-2,-5).

kodGreya [7K]

Answer:

72.14 units

Step-by-step explanation:

Let A(8,13), B(5,-18),C(-6,-6) and D(-2,-5)

Apply the distance formula as;

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Finding the lengths of the segments

For AB

$AB=\sqrt{(5-8)^2+(-18-13)^2} =\sqrt{(-3^2)+(-31^2)} =\sqrt{970} =31.14$

For BC

$BC=\sqrt{(-6-5)^2+(-6--18)^2} =\sqrt{(-11^2)+12^2} =\sqrt{265} =16.28$

For CD

$CD=\sqrt{(-2--6)^2+(-5--6)^2} =\sqrt{4^2+1^2} =\sqrt{16+1} =\sqrt{17} =4.12$

For DA

$DA=\sqrt{(8--2)^2+(13--5)^2} =\sqrt{10^2+18^2} =\sqrt{424} =20.6$

Finding the perimeter will be;

31.14+16.28+4.12+20.6=72.14 units

3 0

3 years ago

Which set of line segments could create a right triangle?

ser-zykov [4K]

Answer:

15,36,39

Step-by-step explanation:

A right triangle will satisfy Pythagoras Theorem:

c² = a² + b²; where c is the longest side.

8 0

3 years ago

Calculate the maturity value of a loan if borrowing 5000 at 7% simple interest for 48 months

Monica [59]

The total is 6400, but if subtracted, its 1400

6 0

3 years ago

Read 2 more answers

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

8 0

3 years ago