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3 years ago

Factor completely the expression: 2x^3 - 2x^2 - 12.

Mathematics

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

2(x^3-x^2-6)

Step-by-step explanation:

2 out of 2x^3 - 2x^2 - 12

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Solve the inequality: -2z - 3 < 5

Ghella [55]

Answer:

z>-4

Step-by-step explanation:

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2 years ago

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jake makes 9 loaves of olive bread. he uses 30 grams of olives in each loaf.he started with 1 kilogram of olives.how many grams

8090 [49]

Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.

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3 years ago

Karen batting average was 0.444 She was at bat 45 times.how many hits did she get?

Simora [160]

<span>Karen got an average of 0.444 hits out of 45 bats.
We need to find the number of hits did Karen got.
=> 45 bats all in all
=> 0.444 average hits
x = how many hit did she get
Now, let’s multiply the total bats to Karen’s average hit:
=> 45 x 0.444 …. (repeating decimals)
=> 20
Therefore, Karen hit 20 times out of 45 bats
Let’s check our answer:
=> 20 / 45
=> 0.44444…. (repeating decimals)

</span>

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3 years ago

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Help Me please11111111

Y_Kistochka [10]

Answer:

The first option im pretty sure

Step-by-step explanation:

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2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago